A ball is thrown vertically in the air with a velocity of 160ft/s. Use the projectile formula h=−16t2+v0t to determine at what time(s), in seconds, the ball is at a height of 384ft.
Accepted Solution
A:
Answer:2 secondsStep-by-step explanation:You are given an equation, a height, and a velocity. Using this you need to solve for t:[tex]384=-16t^2+160t\\16t^2-160t+384=0\\t^2-10t+24=0\\(t-6)(t-4)=0\\t=4, 6[/tex]We get 2 answers for t. This is because the ball is at 384ft twice - once on its way up, and again on its way down. The ball is at (or above) 384ft for 6 - 4 = 2 seconds.