A box with an open top is to be constructed from a square piece of cardboard, 3 ft wide, by cutting out a square from each of the four corners and bending up the sides. Find the largest volume that such a box can have.(a) Draw several diagrams to illustrate the situation, some short boxes with large bases and some tall boxes with small bases. Find the volumes of several such boxes.(b) Draw a diagram illustrating the general situation. Let x denote the length of the side of the square being cut out. Let y denote the length of the base.(c) Write an expression for the volume V in terms of x and y.V =__________. 1(d) Use the given information to write an equation that relates the variables x and y.2(e) Use part (d) to write the volume as a function of x.V(x) =_______________. 3(f) Finish solving the problem by finding the largest volume that such a box can have.V = 4 ft3
Accepted Solution
A:
Answer:a) See annexb) See annex x = 0,5 fty = 2 ft and V = 2 ft³Step-by-step explanation: See annexc) V = y*y*xd-1) y = 3 - 2xd-2) V = (3-2x)* ( 3-2x)* x ⇒ V = (3-2x)²*x V(x) =( 9 + 4x² - 12x )*x ⇒ V(x) = 9x + 4x³ - 12x² Taking derivativesV¨(x) = 9 + 12x² - 24xV¨(x) = 0 ⇒ 12x² -24x +9 = 0 ⇒ 4x² - 8x + 3 = 0Solving for x (second degree equation)x =[ -b ± √b²- 4ac ] / 2awe get x₁ = 1,5 and x₂ = 0,5 We look at y = 3 - 2x and see that the value x₂ is the only valid root thenx = 0,5 fty = 2 ft and V = 0,5*2*2V = 2 ft³